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¦^´_ 8# 198188


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Range([KP!K1], [KP!I65536].End(3))
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Range([KP!J1], [KP!H65536].End(3))
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¥»©«³Ì«á¥Ñ 198188 ©ó 2024-3-4 18:20 ½s¿è

¦^´_ 7# Andy2483



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¦^´_ 6# 198188


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¦^´_ 5# Andy2483



    ¹B¦æVBA¦Z¡AKP内¬O H- J Äæ¨S¦³Åª¨ú¥X¨Ó¡A¥H¦Ü¶À¦â³¡¤À¤£¥¿½T¡C
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¥»©«³Ì«á¥Ñ Andy2483 ©ó 2024-3-4 16:03 ½s¿è

¦^´_ 1# 198188


Option Explicit
Sub TEST()
Dim Arr, Brr, Crr, V$, Z, i&, T$, TT$, A, xA As Range, N%
Set Z = CreateObject("Scripting.Dictionary")
Set xA = Range([1!G1], [1!A65536].End(3))
xA.Offset(1, 12).ClearContents:  Brr = xA
For i = 2 To UBound(Brr)
   T = Format(Trim(Brr(i, 2)), "0000000"): V = Format(Val(Brr(i, 7)), "0000000"): TT = T & "/" & V
   Z(TT) = i
Next
Arr = [1!M1].Resize(UBound(Brr), 3)
A = Array(Range([KH!C1], [KH!A65536].End(3)), Range([KH!J1], [KH!H65536].End(3)), Range([KP!C1], [KP!A65536].End(3)), Range([KP!K1], [KP!I65536].End(3)))
For Each Crr In A
   Crr = Crr: N = N + 1
   For i = 3 To UBound(Crr)
      T = Format(Trim(Crr(i, 1)), "0000000"): V = Format(Val(Crr(i, 2)), "0000000"): TT = T & "/" & V
      If Z.Exists(TT) Then
         If Arr(Z(TT), 1) = "" Then
            Arr(Z(TT), 1) = Crr(1, 1)
            ElseIf InStr("/" & Arr(Z(TT), 1) & "/", "/" & Crr(1, 1) & "/") = 0 Then
            Arr(Z(TT), 1) = Arr(Z(TT), 1) & "/" & Crr(1, 1)
         End If
         Arr(Z(TT), N \ 3 + 2) = Crr(1, 3)
      End If
   Next
Next
[1!M1].Resize(UBound(Brr), 3) = Arr
End Sub
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¦^´_ 3# Andy2483


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¦^´_ 2# 198188


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¦^´_ 1# 198188


    ¹Ï¤ù¬O°õ¦æ«e¤Î°õ¦æ¦Z®ÄªG¡A¥H¤Î¨â­Ó¸ê®Æ®w KP & KH¡C

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