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A1="3D. °¶¤j(¤¤¤åª©)"
B1=IF(LENB(MID($A1,COLUMN()-1,1))=2,MID($A1,COLUMN()-1,1),"")&C1
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lmh

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¦A½Ð±Ðvb¨½lenb¦p¦ó¥Î?
vb¨½ lenb(3)¥X¿ù,lenb("3")=2,¦ó¸Ñ?
lmh

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°ÝÃD¸Ñ¨M¤F
Function ZW(A)
For i = 1 To Len(A)
If LenB(StrConv(Mid(A, i, 1), &H80)) = 2 Then
    zw2 = zw2 & Mid(A, i, 1)
End If
Next i
ZW = zw2
End Function
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lmh

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Function ZW(A)
For i = 1 To Len(A)
If LenB(StrConv(Mid(A, i, 1), &H80)) = 2 Then
    zw2 = zw2 & Mid(A, i, 1)
End If
Next i
ZW = zw2
End Function

®³±¼ StrConv ¨ç¼Æ¦p¤U¡A°õ¦æ´N¤£¹ï¡AWHY?

Function ZW1(A)
ZW = ""
For i = 1 To Len(A)
If LenB(Mid(A, i, 1)) = 2 Then
    ZW = ZW & Mid(A, i, 1)
End If
Next i
End Function
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¥»©«³Ì«á¥Ñ mhl9mhl9 ©ó 2013-8-10 00:50 ½s¿è

§Ú¬O¬Ý¨ì¥H¤U¨â¬qª¾¹Dvba¨½lenb©Mexcelªºlenb¤£¦P
VBA¤¤¡GLenB ªð¦^ªº¬O¥Î¤_¥Nªí¦r²Å¦êªº¦r节数¡A¦Ó¤£¬Oªð¦^¦r²Å¦ê¤¤¦r²Åªº数¶q¡C
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Function LenMbcs(ByVal str As String)
    LenMbcs = LenB(StrConv(str, vbFromUnicode))
End Function
Sub yyy()
a = LenMbcs("¼Babc")
End Sub
a=5------(2+3)
lmh

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¥Î ¡§¥¿³Wªí¥Ü¦¡¡¨

Function CountDblChr(ByVal sCh As String) As Integer

    Set re = CreateObject("vbscript.regexp")

    're.Pattern = "[\u4e00-\u9fa5]" '§PÂ_¤¤¤å¦r(¥]¬A¯S®í¦r¡A¦ý¤£¥]¬A²Å¸¹¡C©M¼Æ¦r¦p¢°¡^

    re.Pattern = "[^\x00-\xff]" '§PÂ_©Ò¦³ªº¥þ§Î¦r

    re.Global = True

    re.IgnoreCase = True

    Set matches = re.Execute(sCh)

    CountDblChr = matches.Count

    Set re = Nothing

End Function
ss

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