°ª¤âÌÀ°À° regexp ¨D±Ð  §ä¯S©w¼Æ¶qªº¼Æ¦r
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 °ª¤âÌÀ°À° regexp ¨D±Ð  §ä¯S©w¼Æ¶qªº¼Æ¦r
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 Private Function format_dn(ByVal DN As String) As String
 
 
 Set oregexp = CreateObject("vbscript.regexp")
 With oregexp
 .Global = True
 .IgnoreCase = True
 .Pattern = "[0-9]+"
 .MultiLine = True
 
 Set omatch = .Execute(DN)
 'MsgBox (omatch(0))
 
 For Each m In omatch
 returntext = returntext & m & vbCrLf
 Next
 format_dn = returntext
 
 'replace the number then exist a-z
 'MsgBox .Replace(DN, "")
 
 
 
 End With
 
 End Function
 
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| ¦^´_ 1# adrian_9832 
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 [A1]="asd1234567890,f0987654321,c3567890,d2456789012,0.34567890132,-0.2547896543,S234,000,F25533.000,G33366666,000000"
 
     
 Option Explicit
 Private Function format_dn(ByVal DN As String) As String
 Dim T$, N&, Y, i
 Set Y = CreateObject("Scripting.Dictionary")
 For i = 1 To Len(DN) - 5
 T = Mid(DN, i, 8): N = Val(T): T = N
 If T Like "2#######" Or T Like "3#######" Then Y(T & "") = ""
 T = Mid(T, 1, 6)
 If T Like "2#####" Or T Like "3#####" Then Y(T & "") = ""
 Next
 If Y.Count = 0 Then
 format_dn = ""
 Else
 format_dn = Join(Y.KEYS, vbCrLf)
 End If
 Set Y = Nothing
 End Function
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| \b[23](\d{5}|\d{7})(?![\d\.]) | 
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| ¦^´_ 1# adrian_9832 ¼Ó¥D¸Õ¸Õ.Pattern = "(2|3)\d{5,7}" ³o¼Ë¤£ª¾¥i§_?
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