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C3=IF(B3>0,B3/10,"")
D3=IF(COUNTA(B3)>0,C3*0.2,"")
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jackson7015 µoªí©ó 2014-9-10 17:02

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ª÷ÃB¥[Á`°_¨Ó¬O 367,024
±N¥¦°£¥H10 ±o¨ì 36,702.4 ­Y¥H ¥|±Ë¤­¤J ¨ÓºâÀ³¬O 36,702 ¦Ó«D 36,703
À³µoªºª÷ÃB¦X­p¬° 36,702(©Î36,703) * 0.2=7,340.48(©Î7,340.6) ¤]¤£À³¸Ó±o¨ì7,332 ³o­Ó¼Æ¦r.

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