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¥»©«³Ì«á¥Ñ singo1232001 ©ó 2022-10-24 15:37 ½s¿è
¦^´_ 1# Andy2483
Sub °õ¦æ³oÓ()
Sheets("¤u§@ªí_1").Range("F:k").ClearContents
test
test2
End Sub
Sub test()
Dim v As String, ve As String
sr = Split("¤u§@ªí_3,¤u§@ªí_4,¤u§@ªí_7", ",")
Set d = CreateObject("scripting.dictionary")
Set s = Sheets("¤u§@ªí_1")
r = s.Cells(Rows.Count, 1).End(3).Row
For i = 1 To r
v = s.Cells(i, 1).Value: ve = Left(v, 1)
If d.exists(ve) = False Then Set d(ve) = CreateObject("scripting.dictionary")
d(ve)(v) = s.Cells(i, 1).Row
Next
ReDim ar(1 To r, 0 To 2) As String
For h = 0 To 2
Set s = Sheets(sr(h))
r = s.Cells(Rows.Count, 1).End(3).Row
For i = 1 To r
ve = s.Cells(i, 1).Value
ar(d(Left(ve, 1))(ve), h) = s.Cells(i, 3).Value
Next
Next
Sheets("¤u§@ªí_1").Cells(1, 6).Resize(r, 3) = ar
End Sub
Sub test2()
Dim v As String, ve As String
sr = Split("¤u§@ªí_2,¤u§@ªí_5,¤u§@ªí_6", ",")
Set d = CreateObject("scripting.dictionary")
Set s = Sheets("¤u§@ªí_1")
r = s.Cells(Rows.Count, 4).End(3).Row
For i = 1 To r
v = s.Cells(i, 4).Value: ve = Left(v, 1)
If d.exists(ve) = False Then Set d(ve) = CreateObject("scripting.dictionary")
d(ve)(v) = s.Cells(i, 4).Row
Next
ReDim ar(1 To r, 0 To 2) As String
For h = 0 To 2
Set s = Sheets(sr(h))
r = s.Cells(Rows.Count, 1).End(3).Row
For i = 1 To r
ve = s.Cells(i, 1).Value
ar(d(Left(ve, 1))(ve), h) = s.Cells(i, 3).Value
Next
Next
Sheets("¤u§@ªí_1").Cells(1, 9).Resize(r, 3) = ar
End Sub
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¥»©«³Ì«á¥Ñ singo1232001 ©ó 2022-10-24 15:50 ½s¿è
¦^´_ 2# singo1232001
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