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Private Sub TextBox1_KeyDown(ByVal KeyCode As MSForms.ReturnInteger, ByVal Shift As Integer)
If KeyCode = 13 Then
MsgBox "§A«ö Enter ·F¹À¡H"
End If
End Sub
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- ©«¤l
- 1572
- ¥DÃD
- 16
- ºëµØ
- 2
- ¿n¤À
- 1521
- ÂI¦W
- 0
- §@·~¨t²Î
- xp
- ³nÅ骩¥»
- office 2003
- ¾\ŪÅv
- 150
- ©Ê§O
- ¨k
- µù¥U®É¶¡
- 2010-5-1
- ³Ì«áµn¿ý
- 2016-1-13

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